Equation of the Plane: Solving for Unknowns | Homework Help

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I think so, ie. one unit across two up
 
but it's not z = f(x,y) = 2y right?? what am I missing here
 
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Homework Statement



http://img245.imageshack.us/img245/7428/equation.th.jpg

Homework Equations





The Attempt at a Solution



I feel really stupid that I can't find the equation of the following... is the y slope here 2?
Don't know what you mean "y slope." This plane appears to by generated by a line in the y-z plane whose slope (dz/dy) is -2. The equation of that line is z = -2y + 2. x is arbitrary.
 
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Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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