Equation p(h): Explained and Derived From Boltzmann's Law

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The equation p(h) = (p0e)^(-mgh/kT) describes the pressure at height h in the atmosphere, derived from principles related to hydrostatic equilibrium rather than directly from Boltzmann's distribution law. In this equation, p0 represents the atmospheric pressure at sea level, m is the mass of an object at height h, g is the acceleration due to gravity, k is Boltzmann's constant, and T is temperature. Euler's number, e, is approximately 2.7 and is crucial for the exponential decay in pressure with height. This equation predicts the number of gas molecules and the pressure at various altitudes, illustrating how atmospheric pressure decreases with height. The discussion clarifies common confusions about the constants involved and emphasizes the equation's application in atmospheric science.
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p(h) = (p0e)-(mgh/kT)

where p0 is the atmosphere at sea level, m is the mass of an object at height h, g is the gravitational proportionality constant...

is there a specific name for this equation? is this derived from the Boltzmann’s distribution law? Also, I'm really confused about what e is... Thank you!
 
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e is Euler's number, about 2.7. Search wiki for it.

It's the pressure at a height, h at a temperature T. k is Boltzmann's constant.
 
Also g is not the same thing as G. G is the gravitational proportionality constant, g is the acceleration due to gravity.
 
Also,the p_o should not be inside the parentheses. Only the e is being raised to that power. It is not a Boltzmann factor, that would be statistical physics. This is a solution to a force equation, the hydrostatic equilibrium that looks like dp/dh = -rho * g, where rho = mp/kT from the ideal gas law and p is gas pressure.
 
And m is the mean molecular mass of air.
 
comparing a flat solar panel of area 2π r² and a hemisphere of the same area, the hemispherical solar panel would only occupy the area π r² of while the flat panel would occupy an entire 2π r² of land. wouldn't the hemispherical version have the same area of panel exposed to the sun, occupy less land space and can therefore increase the number of panels one land can have fitted? this would increase the power output proportionally as well. when I searched it up I wasn't satisfied with...
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