What is the Maximum Temperature for a Given Heat Capacity Equation?

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The discussion focuses on determining the maximum temperature for a given heat capacity equation by solving the equation exp(x) = (x + 2)/(x - 2). The user found a numerical solution of x = 2.4 through trial-and-error, which aligns with textbook results. Participants clarify that there is no elementary solution for this equation due to the complexity of x appearing both inside and outside the exponential function. They suggest using the Lambert W function as an alternative, though it is not necessarily a more straightforward method. The conversation concludes with the user acknowledging the validity of numerical solutions.
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Homework Statement



This regards a question on heat capacity; I'm trying to find the temperature at which the heat capacity is maximum. After differentiating the heat capacity expression, equating to zero, and rearranging (all of which I have omitted), my problem boils down to:

exp(x) = (x + 2)/(x - 2)

Solve for x. (x in this context is theta/T, but I don't think it's relevant since I'm trying to find their ratio)

Homework Equations



See above

The Attempt at a Solution



I calculated x = 2.4 by trial-and-error, and the maximum heat hapacity for this value is in agreement with the my textbook. I just don't know how to solve it properly!
 
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What do you mean by "solve it properly"? A numerical solution is perfectly valid. In this equation, with x both in and outside of the exponential, there is no "elementary" solution. You could try Lambert's W function which is defined as the inverse of the function xex but that is no more "proper" than a numerical solution.
 
Ah, sorry, I just thought there was a "neater" solution that was eluding me. Thanks for clearing that up.
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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