Equations for relative velocity

UglyNakedGuy
Messages
11
Reaction score
0
hello everyone,

Can someone kindly show me the equation for relative velocity calculations?

when i search for them via wikipedia, there is only one formula for collinear objects and they move to the same direction...

so what if they move opposite to each?

and what if their motions follow a curvature ...:confused:

please help :P
 
Physics news on Phys.org
The equation you mention for "relative velocity" is: if object A is moving away from me at velocity u and object B is moving along the same line and in the same direction at speed v (both relative to me) then the speed of object A relative to B is given by
\frac{u- v}{1+ \frac{uv}{c^2}}

If they are moving in opposite directions, replace "-v" with "+v".

If they are not moving along the same line, draw a line between them and calculate their components of velocity parallel and perpendicular to that line. Apply the formula above to the parallel components only.
 
HallsofIvy said:
If they are moving in opposite directions, replace "-v" with "+v".

And replace "+v" with "-v". More concisely, reverse the sign of v everywhere in the equation.
 
HallsofIvy said:
The equation you mention for "relative velocity" is: if object A is moving away from me at velocity u and object B is moving along the same line and in the same direction at speed v (both relative to me) then the speed of object A relative to B is given by
\frac{u- v}{1+ \frac{uv}{c^2}}

If they are moving in opposite directions, replace "-v" with "+v".

If they are not moving along the same line, draw a line between them and calculate their components of velocity parallel and perpendicular to that line. Apply the formula above to the parallel components only.

thank you for your reply!

unfortunately, when I search on website, I was told the equation as:

\frac{u- v}{1- \frac{uv}{c^2}}

and it says if they go opposite directions, I need to replace the sign...if you think I am paranoid :) , please check here http://en.wikipedia.org/wiki/Relative_velocity

to be honestly, I am not a guy with physics background, i just like it... so this is confusing for me... could you please help?

once again, thank you!
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
Back
Top