Equations of motion for an orbit

fasterthanjoao
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Only reason I'm posting here is that i'll get more views than in the cosmology thread, I'm afraid..

(Basically, I'm working through a couple of different models and after some work I'm a bit stuck: http://trond.hjorteland.com/thesis/node21.html

I'm basically trying to integrate equation 3.33 to t_0 - without much success. Now, cosmologists will know that a(t)=(\frac{t}{t_0})^\frac{2}{3} which I feel should be substituted, getting rid of the a^\frac{1}{2}da? Any comments on this appreciated.
 
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This is to help you find the antiderivative: Make the substitutions

a=\Omega_{0} , \ b=1-\Omega_{0}, \ a=y^{3/2}

You get the equation

H_{0}\int{}dt=\frac{2}{3}\int \frac{dy}{\sqrt{by^2 +a}}

Can you take it from here ?
 
Seems to me like it's at least definitely a log, I think roughly coming out to something like :

H_0t=\frac{2}{3}\log(2by+2\sqrt{a+by^2})

Which I'm doesn't seem right, and infact I'm almost certain the final form should be independent of y, since in a limit it should simplify to

H_0t_0=\frac{2}{3}

So it seems I need to at least have a definite integral, ill just say y from 0 to 1 since I've already normalised for y to be 1 at present.
 
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Integrating from 0 to 1 seems to be correct now, from Mathematica I see that it's an inverse hyperbolic sine (through I suppose there's an equivalent form in Log). Could obviously have used Mathematica at the beginning, but I'd like to be able to work through it since it's bugging me now!

If you can shed light on how this is done, that would be great. Thanks.
 
Think I have it ok now, was just a little rusty on my integration. Thanks for the help dextercioby.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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