Equations of motion for disk and spring system

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SUMMARY

The discussion focuses on deriving the equations of motion for a thin uniform disk suspended by two springs, utilizing Newton's second law for both translational and rotational dynamics. The moment of inertia is specified as 0.5mr², where m is the mass and r is the radius of the disk. The equations of motion are established as ΣF=ma and ΣT=Iα, with the forces from the springs represented as Fs=kδ. The user correctly identifies the relationships between the spring displacements and the disk's motion, leading to the formulation of the equations necessary for solving the problem.

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  • Understanding of Newton's laws of motion
  • Familiarity with rotational dynamics and moment of inertia
  • Knowledge of spring mechanics and Hooke's law
  • Ability to manipulate differential equations
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  • Study the derivation of equations of motion for systems involving springs and disks
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  • Explore the concept of moment of inertia in various geometries
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Homework Statement


Thin uniform disk with radius r, mass m, and moment of inertia 0.5mr2 is suspended from a cable line where one end is attached to a set point via a spring, and the other end is also attached to a spring but is moving in an upwards direction. Solve for the equations of motion in terms of x(t) and θ(t).
http://imgur.com/xYwVP79

xYwVP79.png

Homework Equations


ΣF=ma, ΣT=Iα, Fs=kδ

The Attempt at a Solution


Used Newtons 2nd law in terms of rotational and translational inertia. δ1 is change in length of left spring, δ2 is change of length of right spring.

Translational: kδ1 + kδ2 - mg = mx"
Rotational: -kδ1r + kδ2r = 0.5mr2θ"

I set δ1 = rθ and then I set δ2 = xIN-x

Substituted in and just rearranged each equation to have variables one side and constant terms on the other. Is that the correct way to work this problem? Thanks
 
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just in case anyone comes across this... δ1 is actually x-rθ and δ2 is x+rθ... then ΣF=ma turns into -k(x-rθ) - mg + k(x_in-x-rθ) = mx". do the same for rotation and torques then solve
 

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