# Equiangularity of a Polar Equation

1. Mar 1, 2010

### daisukekazama

1. The problem statement, all variables and given/known data
Show that the equation below connects the point $$(r_{0}, \theta_{0})$$ to the point $$(r_{1}, \theta_{1})$$, $$\theta_{0}\neq\theta_{1}$$, along a curve that everywhere forms the same angle with the rays $$\theta=constant$$.

And here's the equation. I can't get the Latex to work... no clue why.

2. Relevant equations
N/A.

3. The attempt at a solution
This is part of a larger problem on stereographic projection - I've figured out that this equation, if projected onto a sphere, traces out a loxodrome. I also know that I essentially have to prove that that mess of an equation is a equiangular spiral (logarithmic spiral).

The problem is, no matter how I look at it, I need to calculate the derivative $$dr/d\theta$$, which - from where I'm looking - looks like one hell of a messy and convoluted derivative, which I'd rather not do.

Is there an easier, cleaner, more elegant way of solving this problem than brute-forcing the derivative? If not, how do I do the derivative?

2. Mar 3, 2010

### Gib Z

I'm not sure whether you have addressed this part of the question or not, but substitution shows that r indeed connects the given points. I'm not sure of a more elegant way at the moment, but the derivative is much easier to calculate if you extract constants in the way r^(x-b) = r^x/r^b.

Then you are left simply in the form $$r= C r_0^{t\theta} r_1^{-t\theta}$$ and apply the product rule.

3. Mar 3, 2010

### daisukekazama

Thank you - that helped.