Equilateral Triangles and Complex Variables: Proving the Relationship

nicksauce
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Homework Statement


Let {z1,z2,z3} be complex variables such that |z1| = |z2| = |z3|. Prove that z1,z2,z3 are vertices of an equilateral triangle iff z1 + z2 + z3 = 0.


Homework Equations





The Attempt at a Solution


Not really sure where to start on this. I know that |z2-z1= |z3-z2| = |z3-z1|, but this information didn't get me very far. Any hints on how I should start this proof, or what other information I will need?
 
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Divide your equation by z1. Now you have 1+z2/z1+z3/z1=0. So you can just work with the case 1+y1+y2=0 and |y1|=1 and |y2|=1. Does that make it seem easier?
 
Thanks that was quite helpful. Just one thing though... in the proof I needed to say that there exists just one equilateral triangle with (1,0) as a vertex, and has all the sides length 1 away from the origin. Is this as obvious as it intuitively seems to me, or do you think I should try to prove it?
 
nicksauce said:
Thanks that was quite helpful. Just one thing though... in the proof I needed to say that there exists just one equilateral triangle with (1,0) as a vertex, and has all the sides length 1 away from the origin. Is this as obvious as it intuitively seems to me, or do you think I should try to prove it?

It may seem obvious, but you still have to prove it. If you have 1+y1+y2=0 and |y1|=|y2|=1, look the the real and imaginary parts of y1 and y2. You can actually solve for them.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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