Equilibrium Constant: H2+O2->H2O

AI Thread Summary
In the discussion, the focus is on the effect of multiplying a chemical reaction equation on the equilibrium constant. When the reaction H2 + 1/2 O2 → H2O is multiplied by 2, the equilibrium constant changes to K^2. This indicates that while the value of the equilibrium constant is altered due to the new stoichiometry, the results of equilibrium calculations remain consistent when the appropriate constant is used in relation to the modified equation. The conversation highlights the distinction between the equilibrium constant's value and its application in calculations, emphasizing that intensive or molar quantities are unaffected by this change.
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H2+1/2 O2 ---------> H20

If the equation is multiplied by 2
Will the equilibrium constant change or remain constant ?
 
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The square of a constant is still a constant.
 
Useful nucleus said:
The square of a constant is still a constant.
Sorry, I don't understand, can you clarify what you mean, thanks.
 
Equilibrium constant will change, but as it will describe different reaction equation, you will find when the correct combination of the equation and constant is used, results of equilibrium calculations are identical.
 
ElmorshedyDr said:
Sorry, I don't understand, can you clarify what you mean, thanks.
Suppose you calculate a constant for the above reaction and its value is K. If you multiply the equation by 2, then the new constant will be K2 .

But this should not matter for any intensive or molar quantity.
 
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