Equilibrium Help: Solving Free Body Diagrams

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The discussion revolves around difficulties in visualizing and drawing free body diagrams for a physics homework problem involving equilibrium. The scenario features a block on a rough table, with an elastic string pulling it at a 45-degree angle, creating both horizontal and vertical forces. Participants emphasize the importance of breaking down the string's force into its components to accurately represent the forces acting on the block. Clarification is provided on how the upward force from the string reduces the normal force on the block. Overall, the conversation highlights the process of constructing effective free body diagrams for complex equilibrium problems.
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Equilibrium help please!

Hi, I'm having problems with one of my homework assignments on equilibrium. I'm fine with all the calculations once I draw up a free body diagram but I'm not particulary good at visualizing the problem etc. :confused: Can anyone help me out with the diagram?

The question is:

A block of mass m is lying on a rough table, the coefficient of friction being µ. One end of an elastic string of modulus λ and natural length l is attached to the block. The other end of the string is pulled in a direction away from the block so that the string is at an angle of 45° to the horizontal.

Thanks for reading!
 
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Sigh. The preformatted text tag doesn't work. I think I knew that.

The string is pulling the block both to the side and upwards at a 45 degree angle. This will give you not only a force tending to make the block slide but one pulling it upward from the table, reducing the normal force exerted on the block by the table (and, via N3, vice versa, of course).

Does that help?
 
hmm I know what you are getting at...but I'm still unsure of how to present the diagram :frown:

What would it look like if it was just a normal sketch of a block with the string? I seem to find it easier to construct the free body diagrams with an initial diagram without the complicated forces.
 
Well, the only difference is that 45 degree angle. If it weren't for that, you'd have the force of the string one way, the force of friction the other, the normal force up and weight down.
As the problem stands, you still have those forces except that the force of the string needs to be broken into components, one vertical and one horizontal.
 
I get it nowz, thanks for your help! :D
 
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