The concentration will decrease because the volume will increase. This will make Q lower than the K value so the forward reaction should be favored(shifts right)
The concentration will decrease because the volume will increase. This will make Q lower than the K value so the forward reaction should be favored(shifts right)
Quite the opposite, the more diluted the solution, the more dissociated the complex is.
By adding water the rate of the forward reaction decreases X to the power 2 times while the rate of the backward reaction will decrease only X times so the reaction moves backwards
Pretend the Keq is 1, and all species' molarity is 1 at the equilibrium. Now do the dilution recalculate Q based on the new concentrations. Compare Q with Keq and reason it out.