Equivalent Circuit: Re-Draw OK?

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Redrawing the equivalent circuit is not acceptable due to discrepancies in node connections. The original circuit has the 4 Ω and 6 Ω resistors sharing a node, which is not maintained in the proposed redraw. Additionally, the new configuration incorrectly implies relationships between the currents I1, I2, and I3. To correct the redraw, a wire must be added to connect specific points in the circuit. Accurate representation of circuit elements is crucial for proper analysis.
princejan7
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Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/

as this
http://postimg.org/image/uvtf6f8vv/


?
 
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Hello, your higness. Not your first post, so you should know better by now. Use the template and don't make me chase links instead of going to sleep. Maybe tomorrow.

But, out of curiosity: is the central point in the first picture a connection or is I1 = -I3 ?
 
Whether the central point is connected or not, the redrawing is not correct. One discrepancy (and there are others): in the original drawing, the 4 Ω and the 6 Ω share a node. In the redrawing, they do not.
 
princejan7 said:
Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/

as this
http://postimg.org/image/uvtf6f8vv/

?
No


attachment.php?attachmentid=66728&stc=1&d=1392691615.png


Is not the same as

attachment.php?attachmentid=66729&stc=1&d=1392691712.png


Your circuit would force I3 = -I2

and I1 = 1 Amp
 

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It would be correct if you add a wire from the point between the 4 and 12 ohm resistors at the bottom to the point between the 6 ohm resistor and the 1 amp current source at the top. You separated the 4 wires coming together in the midpoint into 2 pairs.
 
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