(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the current flowing through the voltage source in mA. Assume Vs = 3.9 V and R = 8.3 kohm. Round off your answer to two decimal points.

2. Relevant equations

1/R(equivalent) = 1/R1 + 1/R2 + ...

I=V/R

Kirchoff's voltage law

3. The attempt at a solution

I considered the 3 resistors in the upper left of diagram (10k, R=8.3k, 10k) to be in parallel and calculated their equivalent resistance to be 3.12 kOhms. I basically ignored the two 10kOhm resistors in the bottom right because a) they didn't seem to be in series, or parallel so I didn't know what to do with them and b) it seemed that the current would avoid them by taking the path of least resistance after going through the 3 resistors in parallel in the upper left. I then wrote the KVL equation: Vs - I(3.12*10^3) = 0 and solved for I determining the current to be 1.25mA.

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# Homework Help: Equivalent resistance with possible short circuit

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