Essentially comparison of isothermal and adiabatic transformations

AI Thread Summary
In the discussion, two identical samples of ideal gas undergo different transformations: one is isothermal and the other adiabatic. The isothermal transformation maintains constant temperature, leading to a relationship where pressure decreases as volume increases. Conversely, the adiabatic transformation involves no heat exchange, resulting in a decrease in pressure with a corresponding change in volume. The key question is whether V2 is higher or lower than V1, given that P3 is less than P2. The analysis suggests that V2 is likely greater than V1, but the reasoning requires a deeper understanding of the equations governing each transformation.
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Homework Statement




Two identical samples of ideal gas are initially at P1 and V1. The first sample undergoes an isothermal transformation to P2, V2 and second sample undergoes an adiabatic transformation to P3, V2. If P3<P2, is V2 higher or lower than V1? Explain



Homework Equations



Ideal Gas Law, Thermo Laws.

The Attempt at a Solution



P1V1 --isotherm-->P2V2
P1V1 --adiabatic-->P3V2
If P2>P3, is V2>V1 or V2<V1?
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For isotherm we have ΔU=Q+W, but since there is ΔT=0, then via 1st law of Thermo - ΔU=0 and Q=-W.
For adiabatic we have constant heat, Q=0, W=PΔV, ΔU=W=PΔV. Yet... it seems useless. My gut tells me V2>V1, though somehow I am having trouble wrapping my mind around it.
 
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There are two very useful equations relating pressure and volume, one for isothermal and one for adiabatic. You've met these, I would think.
 
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