Estimate the density of the water

AI Thread Summary
To estimate the density of water at a depth of 5.7 km in the sea, the bulk modulus (B) of water is given as 2.0 x 10^9 N/m^2. The pressure at this depth can be calculated using the equation P = ρgh, but the user is unsure how to proceed without knowing the pressure. Suggestions include assuming a uniform pressure for estimation purposes, despite acknowledging that pressure changes with depth. A method is provided to relate density changes to pressure changes using the bulk modulus, allowing for the calculation of the density at depth compared to surface density. The discussion emphasizes the importance of understanding how pressure affects water density at significant depths.
kritzy
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Homework Statement


Estimate the density of the water 5.7 km deep in the sea. (bulk modulus for water is B=2.0 x 10^9 N/m^2) By what fraction does it differ from the density at the surface?

Homework Equations


P=(rho)gh=F/A=B(delta l/l)

The Attempt at a Solution


So I have several equations above. I wanted so solve for rho using the first equation but I don't know pressure. I tried the second equations but I don't know Force or area. I tried the last equation but I would need delta l and l so basically I'm stuck. Some advice would be much appreciated.
 
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kritzy said:
Estimate the density of the water 5.7 km deep in the sea. (bulk modulus for water is B=2.0 x 10^9 N/m^2) By what fraction does it differ from the density at the surface?

Homework Equations


P=(rho)gh=F/A=B(delta l/l)

The Attempt at a Solution


So I have several equations above. I wanted so solve for rho using the first equation but I don't know pressure. I tried the second equations but I don't know Force or area. I tried the last equation but I would need delta l and l so basically I'm stuck. Some advice would be much appreciated.

Well they do say estimate. So maybe try to work it out assuming that p doesn't change?

(Yes it changes, but does it change enough to matter? See what results you get and then decide.)
 
LowlyPion said:
Well they do say estimate. So maybe try to work it out assuming that p doesn't change?

(Yes it changes, but does it change enough to matter? See what results you get and then decide.)

I don't understand. I'm suppose to be solving for p at a certain density. How can it not change?
 
kritzy said:
I don't understand. I'm suppose to be solving for p at a certain density. How can it not change?

Have you calculated it using a uniform p as to the effect it will have on a bulk modulus of 2 * 109?
 
In 6 km, the change in pressure is significant.

Here's something to get you started:

Use the equation,

B=dP/(d(rho)/rho)

Manipulate and integrate,

integral of (d(rho)/rho) = integral of (dP/B)

That results in,

ln(rho2/rho1)=exp((P2-P1)/B)

Where you can say state 1 is the surface, and state 2 is the state at 5.7 km down.

You can then use the rho*g*h equation.
 
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