Estimating cot(46°) Using Method of Differentials

Sethka
Messages
13
Reaction score
0
I am completely lost on these differentials! Can anyone help me make sense of them? Especially this question in particular:

cot(46(deg))

(Sorry, I don't know how to make that small little circle thing that denotes degree)

I'm supposed to use the method of differentials to estimate it to 4 decimal places.

Thanks!
 
Physics news on Phys.org
Show what you've tried. Do you know how to use this method?

By the way, I'd never heard of the "method of differentials" before, and I had to do a google search to figure out what it is. It seems to just be synonomous with "linear approximation", or, if you want a higher order approximation, "taylor series approximation", by which names I think the method is much more well known. Just another reason to always show your work if you want help.
 
45 degrees is \frac{\pi}{4} radians. 1 degree is \frac{\pi}{180} radians. It's better to use radians because that way the derivative is easier: if x is measured in radians then the derivative of y= cos(x) is y'= -sin(x) and so the differential is dy= -sin(x)dx. y+ dy= cos(x)- sin(x)dx.
To find cos(\frac{pi}{4}+ \frac{\pi}{180}, let x= \frac{\pi}{4} so that y= cos(\frac{\pi}{4})= \frac{\sqrt{2}}{2}, -sin(x)= -sin(\frac{\pi}{4})= -\frac{\sqrt{2}}{2} and dx= \frac{\pi}{180}.
 
Oh Thanks!

Thanks you guys, My textbooks are a little backwards it seems. Where one asks me to use method of differentials the other teaches linear aproximation, that was so confusing and now I see why. Thanks A bunch!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top