Euler-Lagrange equation application

Ascendant78
Messages
327
Reaction score
0

Homework Statement



Screen_Shot001.jpg


Homework Equations



Screen_Shot002.jpg


The Attempt at a Solution



I have tried manipulating the equation a few different ways, but the Euler-Lagrange and the one I'm supposed to show for a) is so different that I just can't seem to work. Can someone please point me in the right direction here?
 
Physics news on Phys.org
I think you don't need the Euler-Lagrange equation for (a). That looks like the standard derivative, just calculate it.
 
Well, just calculating the derivative, I'm not sure why it is coming out the way it is? I get that the "t" component would be zeros, cancelling out its parts. However, I'm not sure what derivative/partial derivative rules are being applied to get the equation to look like the one asked for in a)?
 
Think chain rule. If you still can't figure it out, show us your attempt.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top