Evaluate Integral: Find Derivative of Exp(-t^2)

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SUMMARY

The discussion focuses on evaluating the derivative of the integral \(\frac{d}{dx} \int _{x}^{tanx}exp(-t^2)dt\). The solution involves substituting variables to convert the lower limit into a constant and the upper limit into a variable with a constant derivative. By defining \(F(t) = \int exp(-t^2)dt\), the integral can be expressed as \(F(tanx) - F(x)\). The chain rule is then applied to differentiate this expression effectively.

PREREQUISITES
  • Understanding of calculus, specifically the Fundamental Theorem of Calculus.
  • Knowledge of differentiation techniques, including the chain rule.
  • Familiarity with integral notation and properties of definite integrals.
  • Basic understanding of exponential functions, particularly \(exp(-t^2)\).
NEXT STEPS
  • Study the Fundamental Theorem of Calculus in detail.
  • Learn advanced differentiation techniques, focusing on the chain rule.
  • Explore the properties of the error function, related to \(exp(-t^2)\).
  • Practice evaluating derivatives of integrals with variable limits using different functions.
USEFUL FOR

Students and educators in calculus, mathematicians focusing on integral calculus, and anyone interested in advanced differentiation techniques.

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Homework Statement


How would you evaluate

[tex]\frac{d}{dx} \int _{x}^{tanx}exp(-t^2)dt[/tex] ?


Homework Equations





The Attempt at a Solution



So I think you want to substitute variables int order to get the lower limit a constant and the upper limit a variable with constant derivative. Then we just take out the derivative operator and the integral sign. I just cannot think of the right substitution...
 
Last edited:
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let [tex]\int exp(-t^2)dt = F(t)[/tex],

then, [tex]\int _{x}^{tanx}exp(-t^2)dt =<br /> F(tanx)-F(x)[/tex]

then use the chain rule to differentiate, since you already know the derivative of [tex]F(x)[/tex].
 
That works. Thanks.
 

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