JG89
- 724
- 1
Homework Statement
Evaluate \int_{-1}^1 (x^5 + 3) \sqrt{1 - x^2} dx without doing any computations.
Homework Equations
The Attempt at a Solution
\int_{-1}^1 (x^5 + 3) \sqrt{1 - x^2}dx = \int_{-1}^1 x^5 \sqrt{1-x^2} dx + \int_{-1}^1 3 \sqrt{1 - x^2}.
x^5 \sqrt{1 - x^2} is an odd function and 3 \sqrt{1 - x^2} is an even function. So obviously \int_{-1}^1 x^5 \sqrt{1-x^2} dx = 0 and \int_{-1}^1 3 \sqrt{1-x^2} dx = 3 \int_{-1}^1 \sqrt{1-x^2} dx = 6 \int_0^1 \sqrt{1 - x^2} dx. And so:
\int_{-1}^1 (x^5 + 3) \sqrt{1 - x^2} dx = 6 \int_0^1 \sqrt{1 - x^2} dx.
If I am to do this without any computations, then this is the closest answer I could give (that I could think of). Is this answer acceptable?