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Evaluate the definite integral.

  1. Jan 29, 2012 #1
    1. The problem statement, all variables and given/known data

    Integrate from 0 to 1


    2. Relevant equations

    3. The attempt at a solution

    u = -x48

    du = -48x47dx

    dx = du / -48x47

    ∫eu * du/-48

    -[itex]\frac{1}{48}[/itex] ∫ eu du

    -[itex]\frac{1}{48}[/itex] eu

    -[itex]\frac{1}{48}[/itex] e1 - ( -[itex]\frac{1}{48}[/itex] e0)

    -[itex]\frac{e}{48}[/itex] + [itex]\frac{1}{48}[/itex]


    What did I do wrong? Webassign marked this as incorrect but I redid it and got same answer.
  2. jcsd
  3. Jan 29, 2012 #2


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    When x=1, u=-1.
  4. Jan 29, 2012 #3

    Char. Limit

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    Gold Member

    Here's your problem. e^(-(1)^(48)) = e^(-1), not e^1.
  5. Jan 29, 2012 #4
    I see what I did wrong now, thank you.
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