Evaluate the definite integral.

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Homework Help Overview

The discussion revolves around evaluating the definite integral of the function x47e-x48 from 0 to 1. Participants are exploring the integration process and addressing errors in their calculations.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts integration by substitution, defining u as -x48 and deriving the corresponding differential. They express concern over a result marked incorrect by Webassign, prompting questions about their method.

Discussion Status

Participants are actively engaging with the original poster's calculations. One participant identifies a specific error in the evaluation of the exponential function at the limits of integration, which leads to a realization of the mistake by the original poster.

Contextual Notes

There is an indication that the original poster is using an online homework platform that has marked their answer incorrect, which may influence their approach and the urgency of the discussion.

neosonata
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Homework Statement



Integrate from 0 to 1

x47e-x48

Homework Equations





The Attempt at a Solution



u = -x48

du = -48x47dx

dx = du / -48x47


∫eu * du/-48

-[itex]\frac{1}{48}[/itex] ∫ eu du

-[itex]\frac{1}{48}[/itex] eu


-[itex]\frac{1}{48}[/itex] e1 - ( -[itex]\frac{1}{48}[/itex] e0)


-[itex]\frac{e}{48}[/itex] + [itex]\frac{1}{48}[/itex]


[itex]\frac{1-e}{48}[/itex]



What did I do wrong? Webassign marked this as incorrect but I redid it and got same answer.
 
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When x=1, u=-1.
 
neosonata said:
-[itex]\frac{1}{48}[/itex] e-1 - ( -[itex]\frac{1}{48}[/itex] e0)

Here's your problem. e^(-(1)^(48)) = e^(-1), not e^1.
 
I see what I did wrong now, thank you.
 

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