Evaluate the iterated intergal by converting to polar coordinate?

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The discussion focuses on evaluating an iterated integral by converting it to polar coordinates. Participants emphasize the need to convert the differential area element from dxdy to polar coordinates (r and θ) and to adjust the limits accordingly. The integral in question is initially set with specific limits for x and y, but there is a reminder that the upper limit for r will depend on θ. The conversion of the boundary condition y² ≤ 2x - x² into polar coordinates is also highlighted as a crucial step. Overall, the conversation centers on the correct approach to transforming the integral for evaluation.
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ZuzooVn said:
Help me Evaluate the iterated intergal by converting to polar coordinate:


http://www.ziddu.com/gallery/4894419/Untitled.jpg.html

hmm … that's \int_0^2\int_0^{\sqrt{2x-x^2}}\sqrt{x^2+y^2} dxdy

ok … I assume you know how to convert dxdy into r and θ

and for the limits, convert y2 ≤ 2x - x2 into r and θ also :wink:
 
tiny-tim said:
hmm … that's \int_0^2\int_0^{\sqrt{2x-x^2}}\sqrt{x^2+y^2} dxdy

ok … I assume you know how to convert dxdy into r and θ

and for the limits, convert y2 ≤ 2x - x2 into r and θ also :wink:

0≤y≤1
0≤x≤2
0≤r≤2
0≤θ≤ pi/2
:smile:
 
ZuzooVn said:
0≤y≤1
0≤x≤2
0≤r≤2
0≤θ≤ pi/2
:smile:

(have a pi: π :wink:)

No, the upper limit of r will depend on θ.

I repeat … convert y2 ≤ 2x - x2 into r and θ
 
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