- #1
Johnnycab
- 26
- 0
Im asked to evaluate:
[(1/x+4)-1/4]/x
Lim -> 0
Substitution, factoring and conjugate multiplication don't work
The question tells me to multipy the top and bottam by the lcd of the little fractions namely 4(x+4)
--here I am a little confused, did all the book do is take both denominators (x+4) and 4 and make them the LCD together?
So like if my question was for example like this,
[(1/2x+3)-1/4]/x
My LCD would be 4(2x+3), am i wrong?
Thanks
[(1/x+4)-1/4]/x
Lim -> 0
Substitution, factoring and conjugate multiplication don't work
The question tells me to multipy the top and bottam by the lcd of the little fractions namely 4(x+4)
--here I am a little confused, did all the book do is take both denominators (x+4) and 4 and make them the LCD together?
So like if my question was for example like this,
[(1/2x+3)-1/4]/x
My LCD would be 4(2x+3), am i wrong?
Thanks