Evaluating (ln^2) in Easy Math Problem: X=Xo*e^(ln^2/Td)*T | Answer: Xo=17

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Discussion Overview

The discussion revolves around the evaluation of the expression (ln^2) in the context of a mathematical problem involving an equation for X, where participants are trying to understand how to derive the value of Xo given specific parameters.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions the meaning of (ln^2) in the equation, expressing confusion about its definition compared to typical logarithmic expressions.
  • Another participant suggests that (ln^2) might be a misinterpretation and proposes it could simply be ln(2).
  • A different participant attempts to use ln(2) but finds that it does not yield the expected answer of 17 for Xo.
  • One participant later indicates they have resolved their confusion without elaborating on the solution.
  • A comment reflects on the nature of the discussion, noting the humor in quickly resolving a complex question.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the definition of (ln^2), and multiple interpretations are presented without resolution. The discussion remains somewhat unresolved regarding the correct approach to evaluating (ln^2).

Contextual Notes

There are limitations in the clarity of the expression (ln^2) and its intended meaning, which affects the participants' ability to arrive at a consistent solution. The discussion also lacks a detailed exploration of the mathematical steps involved in deriving Xo.

Who May Find This Useful

This discussion may be of interest to individuals exploring logarithmic functions, mathematical problem-solving, or those curious about the nuances of mathematical notation.

bmed90
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So if

Equation: X=Xo*[e^(ln^2)/Td] * T

with

X = 5e12
Td = 15
T= 672

And the answer is Xo=17


My question: is how do I evaluate (ln^2) ??
Usually when I use the ln function to calculate something its like ln(5/2)^2 or something like that but here its just ln^2


what does this mean? How do you get 17 for Xo
 
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Wait ##\ln ^2##? That's not defined. Maybe it should be just ln(2)
 
I used ln(2) but that did not give me an answer of 17
 
Nvm I got. Thanks
 
I think it would have funny if you had posted some unproven conjecture and then moments later posted "nvm, got it."

Just a thought..
 

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