Evaluating the non-relativistic Action

[wam_mi]

Homework Statement

Consider the classical action (m/2) \int dt \dot{x}^{2} where m is the mass of the non-relativistic point particle, and \dot{x} = dx/dt .

This classical path starts at (x_{1}, t_{1}) and ends at (x_{2}, t_{2}). Could someone help me evaluate this classical action explicitly please?

Homework Equations

The Attempt at a Solution

Thanks a lot!

 

[Altabeh]

Homework Statement

Consider the classical action (m/2) \int dt \dot{x}^{2} where m is the mass of the non-relativistic point particle, and \dot{x} = dx/dt .

This classical path starts at (x_{1}, t_{1}) and ends at (x_{2}, t_{2}). Could someone help me evaluate this classical action explicitly please?

Homework Equations

The Attempt at a Solution

Thanks a lot!

Simply add the time bounds of the path to the integral to get

(m/2) \int^{t_2}_{t_1} \dot{x}^{2}dt.

Now turn this into a position-bounded integral as follows:

(m/2) \int^{t_2}_{t_1} \dot{x}^{2}dt=(m/2) \int^{x_2}_{x_1} \dot{x}dx.

Finally take the time derivative out of integrand and solve the integral!

AB

 

[wam_mi]

Simply add the time bounds of the path to the integral to get

(m/2) \int^{t_2}_{t_1} \dot{x}^{2}dt.

Now turn this into a position-bounded integral as follows:

(m/2) \int^{t_2}_{t_1} \dot{x}^{2}dt=(m/2) \int^{x_2}_{x_1} \dot{x}dx.

Finally take the time derivative out of integrand and solve the integral!

AB

Hi there,

Could you kindly explain why one can turn the time-bounded integral into a position-bounded integral?

Thanks a lot!

 

[Altabeh]

Hi there,

Could you kindly explain why one can turn the time-bounded integral into a position-bounded integral?

Thanks a lot!

As in the classical theory of action integrals, the bounds must be either spatial or temporal, so we cannot do the analysis over the dynamics of particles along a bounded path with both elements of time and space simultaneously. So in the integral in question, you can use the chain rule to kill two of time differentials dt by expanding one of \dot{x}'s and cancelling out dt's to only have a dx left behind. The remaining is straightforward to be treated. Since now integral element is dx, so the bound must be spatial and then you can easily factor the operator d/dt out of the integral to get

\frac{m}{2}\frac{d}{dt}\int^{x_2}_{x_1} x dx.

Is it all clear now?

AB