Every open subset of R^p is the union of countable collection of

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Every open sub set of Rp is the union of countable collection of closed sets.

I am attaching my attempt as an image file. Please guide me on how I should move ahead. Thank you very much for your help.
 

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Take an irrational number ##a## in ##G##. You can find a certain open ball ##B(a,\varepsilon)## which remains in ##G##. What can you tell about the rational numbers in that ball? In particular, if ##q\in B(a,\varepsilon)## is rational, what can you tell about the closed set in the hint?
 
This is equivalent to R^p being 2nd-countable.
 
I think I got it. Thank you for your comments
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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