Examining Forces in a Symmetric Building

AI Thread Summary
The discussion focuses on calculating the horizontal force exerted by a symmetric roof sloping at 34 degrees, with each side weighing 1.10×10^4 N. Participants are exploring how to break down the forces into x and y components and considering the application of torque in their calculations. There is uncertainty about setting up the equations correctly, with a request for guidance. Additionally, the potential risk of building collapse is debated, with taller walls being considered more vulnerable due to a higher center of mass. The conversation highlights the importance of understanding force dynamics in structural engineering.
iamwilson
Messages
12
Reaction score
0

Homework Statement



A symmetric building has a roof sloping upward at 34.0 degrees above the horizontal on each side.

A)If each side of the uniform roof weighs 1.10×10^4N , find the horizontal force that this roof exerts at the top of the wall, which tends to push out the walls.

B)Which type of building would be more in danger of collapsing: one with tall walls or one with short walls? Explain

Homework Equations





The Attempt at a Solution


I tried to break the forces into x and y components, x is horizontal so i thought that is the horizontal force.
I also tried use sum of the torque equals zero, but i don't know how to set it up
can someone give me some clues. thanks. It's due tomorrow!
 
Physics news on Phys.org
All I can think of is taller walls having higher centres of mass, therefore would topple more easily.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top