Excited atom decaying to ground state

AI Thread Summary
An excited atom decaying to its ground state emits a photon of green light, while decaying to an intermediate state involves a smaller energy gap. This smaller energy difference results in a lower frequency photon being emitted. The discussions clarify that a smaller change in energy correlates with lower frequencies, suggesting emitted light could be red or orange rather than blue or violet. The relationship between energy and frequency is governed by the equation E = hf, where h is Planck's constant. Understanding these principles is crucial for grasping atomic transitions and photon emissions.
Cataklyzm
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Hello.
I'm trying to grasp this concept. The question states:
An excited atom decays to its ground state and emits a photon of green light. If instead the atom decays to an intermediate state, what color of light might be emitted?

I have the electromagnetic spectrum with the visible lights broken down.
Am I supposed to understand that an atom decaying to an intermediate state wouldn't use as much energy as an atom decaying to ground state?
Something like E = hf. So because of the decrease in energy, there is an increase in frequency, so the emitted light might be Blue or Violet, which have higher frequencies than green?

Am I on the right track?

Thanks,

Cataklyzm
 
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Nope, if it decays into an intermediate state, then the energy gap b/w the levels will be smaller, hence the frequency of the radiated photon.

Daniel.
 
Ohh okay.
So the CHANGE in energy between the excited state and intermediate state is smaller than the change in energy between the excited state and the ground state.

So the equation: Change in energy = h * f provides:
A smaller change in energy creates a higher frequency photon.
Violet and blue have higher frequencies than green.
Therefore, the emitted light would be violet or blue.

Thank you.
 
No way, if the energy is smaller, then the frequency would be smaller, since they are directly proportional. So i'd say rather yellow or orange.

Daniel.
 
Ohhhh.. okay.
I don't know how I didn't see that.
Becuase h is Planck's constant, difference in energy is proportional to frequency.. so it would be a lower frequency photon.. like red or orange..
Got it..
=)
Thanks
 
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