Experiment, magnetic forces between current-carrying wires

AI Thread Summary
Decreasing the variable resistor increases the current in the coil on the weighing scale, which may decrease the weight reading due to the attractive magnetic force between the two coils. The wires are taped to prevent movement caused by the magnetic field generated by the current-carrying coil. If the weight decreases as current increases, the magnetic force is confirmed to be attractive, pulling the coils together. The direction of the current in the fixed coil is crucial to determine the nature of the magnetic interaction. Understanding the current direction in both coils is essential for resolving the magnetic force's behavior.
Cade
Messages
90
Reaction score
0

Homework Statement



There is a coil placed on a very sensitive weighing scale that has a variable resistor attached it to control its current, and is also connected to a power supply. The wires to it have tape to hold them in place. There is another coil held a few millimeters above this coil and fixed in place to the wall, it has current flowing through it, but I don't know which direction it flows in. I also don't know which direction the current flows in the coil that is on the weighing scale.

1) Does decreasing the variable resistor's setting increase or decrease the weight read on the weighing scale? Is the magnetic force attractive or repulsive?

2) Why are the wires with current through them, with which the coil is connected to the resistor and power supply, taped?

3) If the weight decreases as current increases, is the magnetic force attractive or repulsive?

Homework Equations



Decreasing the resistance increases the current.
Magnetic force on a current carrying wire F = ILB
Magnetic field produced by a straight wire (but I have a coil) B = u0*I/(2*pi*r)

The Attempt at a Solution



If the magnetic force exerted by current-carrying wire coil is attractive towards the fixed coil above it, it will counteract gravity slightly and decrease the weight reading on the weighing scale. But I don't know whether force exerted by the current-carrying coil on the weighing scale is attractive or repulsive to the fixed coil above it.

The wires are taped to stop the magnetic field exerted by the current-carrying coil from moving them.

If the weight decreases, the magnetic force is attractive (i.e. pulls upwards).
 
Last edited:
Physics news on Phys.org
In bar magnets, the attractive force is between opposite poles, so I suppose that the force is attractive, but the issue is that I don't know which direction the current flows in the top coil.
 
Two bar magnet ends attract when their magnetization currents flow the same way, likewise coil ends that carry current in the same direction will attract.
 
Yes, but to solve my problem, I first need to know if the current in both coils is in the same direction, or if one is going the opposite way. :smile:

Edit: The question in which it results that they are attractive (3) is a hypothetical question that is separate from (1).
 
If the weight of the one coil is reduced then the currents go in the same direction.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top