Explain two different methods for using combinations

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SUMMARY

The discussion focuses on calculating combinations for a scenario where a soccer coach must select students for a bus trip, with 50 students and only 47 seats available. The two methods for determining the combinations are: selecting 45 students to travel by bus (50 C 45) and selecting 5 students to travel by car (50 C 5). Both methods yield the same result, confirming that the number of combinations is 2,118,760. This illustrates the principle of combinations in combinatorial mathematics.

PREREQUISITES
  • Understanding of combinations in combinatorial mathematics
  • Familiarity with the binomial coefficient notation (n C k)
  • Basic knowledge of factorial calculations
  • Ability to apply combinatorial principles to real-world scenarios
NEXT STEPS
  • Study the concept of binomial coefficients in depth
  • Learn how to calculate combinations using factorials
  • Explore practical applications of combinations in probability theory
  • Investigate variations of combination problems, such as permutations
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Students studying combinatorial mathematics, educators teaching probability and statistics, and anyone interested in applying mathematical principles to real-world problems.

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Homework Statement



A soccer coach organizing a field trip finds that 50 students have signed up. However, the bus has only 47 seats, so a few students will have to travel by car. The coach and one other coach must go on the bus. Explain two different methods for using combinations to find how each coach can choose which students go on the bus. Show that both methods produce the same answer.

Homework Equations





The Attempt at a Solution



I determined that the number of combinations of students on the bus is 50 C 45 = 2118760. However, I do not know how this can be done with two different methods. Could someone please help me? Thanks.
 
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I am not certain to what the question is referring, but it could be the following: for every 45 students that travel by bus there are 5 students that travel by car. We can either choose the 45 bus students (method 1) or we can choose the 5 car students (method 2).
 

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