Why is the a=dv/dt equation used in integration and when is it applicable?

  • Thread starter Thread starter vijay_singh
  • Start date Start date
AI Thread Summary
The equation a = dv/dt represents the derivative of velocity (v) with respect to time (t), allowing for the expression dv = a dt in differential form. This relationship is utilized in integration, particularly through variable substitution, where the integral of acceleration (a) can be transformed into an integral of velocity (dv). The discussion emphasizes that while dv/dt is a mathematical formula, the notation dv = a dt can be misleading, as it simplifies the integration process but may obscure the underlying variable relationships. The limits of integration must be carefully considered, as they pertain to different variables. Overall, the use of dv = a dt is a notational convenience in calculus, particularly in physics.
vijay_singh
Messages
28
Reaction score
0
I see in many text that a = dv/dt implies that

dv = a dt

How is that possible, can anybody please explain me. As far as i know dv/dt is a symbol for derivative of v w.r.t t and not ratio between dv and dt.
 
Physics news on Phys.org
What you wrote is in differential form.
 
dv/dt is not a symbol. It is the mathematical formula for the derivative of v with respect to t. This is how one would show any derivative of a dependent variable with respect to an independent variable.
 
bucher said:
dv/dt is not a symbol. It is the mathematical formula for the derivative of v with respect to t. This is how one would show any derivative of a dependent variable with respect to an independent variable.

And what did I say :-)
 
Now, WHY can we utilize at times the dv=adt formula, in particular, WHERE is it usable?

Answer:

When doing integration with the technique called substitution of variables (i.e the "inverse" of the chain rule):

Given a=dv/dt, we have, trivially:
\int_{t_{1}}^{t_{2}}adt=\int_{t_{1}}^{t_{2}}\frac{dv}{dt}dt
But the right-hand side can, by the theorem of substitution of variables, be reformulated, giving the identity:
\int_{t_{1}}^{t_{2}}adt=\int_{v(t_{1})}^{v(t_{2})}dv=\int_{v_{1}}^{v_{2}}dv

Now, by IGNORING that the limits of integration actually refers to the limits of DIFFERENT variables, we "may say" that the "integrands" are equal, i.e, adt=dv!


Thus, adt=dv should, at this stage of your education, be regarded as notational garnish (or garbage, if you like!)
 
Back
Top