Explaining Forces in Bicycle Riding: How to Help Your Little Brother

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    Bicycle Forces
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When teaching a little brother to ride a bicycle, the force exerted by the teacher is greater than the force exerted by the brother during acceleration due to the need to overcome inertia and initiate movement. As the brother rides and becomes scared, the teacher must exert a greater force to slow him down, again surpassing the force the brother exerts. This dynamic aligns with Newton's laws of motion, particularly the third law, which states that for every action, there is an equal and opposite reaction. Understanding these principles helps clarify the forces at play in both scenarios. The teacher's role is crucial in managing these forces to ensure safety while learning to ride.
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Hi guys, my teacher gave every person in my class a problem to think about over the weekend...it should be pretty easy but let's just say that physics isn't my subject hahaha. well i was hoping you guys could help me out with this, the problem says:

"You are teaching your little brother to ride a bicycle. To get him started while he is speeding up, how does the force you exert on your brother compare to the force he exerts on you? Is the former greater than, less than, or equal to the latter? Explain your reasoning. As he continues to ride along, he gets scared and asks that you stop him so he doesn't fall. While you are slowing him down, how does the magnitude of the force you exert on him compare to the force he exerts on you? Is the former greater than, less than, or equal to the latter? Explain your reasoning."

this is what i was thinking:
1st question - you exert more force on the little brother
2nd question - you still exert more force on him

correct me if I'm wrong, and can somebody help me explain why it's so? thanks!
 
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What are Newton's laws of motion?
 
First Law: Every object in a state of uniform motion tends to remain in that state of motion unless an external force is applied to it.

Second Law: The force of an object is equal to its mass times its acceleration.

Third Law: For every action there is an equal and opposite reaction.
 
sorry for the double post, but can someone please help me? i need to know for tomorrow
 
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