- #1
Dragonfall
- 1,030
- 4
Suppose X is a set consisting of squares with the property that any addition with elements of X (where no two are the same) gives a square (might not be in X). How many elements can X have?
If you use modulus to guide your answer there might be a better method.gnomedt said:There is of course a trivial solution with a set of size 3, which is the Pythagorean "doubles" with the additional element of '0', e.g. {9, 16, 0}.
I've written a program and determined that for 4 <= n <= 9, there is no set of n elements in which every element is unique and the square of some number less than 16, such that addition with any two or more of the elements of the set always gives another square.
Cardinality refers to the number of elements in a set. It is a measure of the size or quantity of a set.
The cardinality of a set can be calculated by counting the number of elements in the set. For example, if a set contains the numbers 1, 2, 3, the cardinality of the set would be 3.
The cardinality of a set of squares depends on the specific set being referenced. For example, if the set contains the squares of all natural numbers from 1 to 10, the cardinality would be 10. However, if the set contains the squares of all real numbers between 0 and 1, the cardinality would be infinite.
The cardinality of a set of squares can be useful in various mathematical and scientific applications. It can be used to determine the size or quantity of a set, as well as to analyze patterns and relationships between numbers.
Yes, it is possible for the cardinality of a set of squares to be greater than the cardinality of its element set. This is because some elements in the set of squares may be repeated, resulting in a larger cardinality than the original set.