What Is the Connection Between Viscosity and Shear Stress in Perfect Fluids?

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A perfect fluid is defined as one that cannot sustain shear stress, meaning that adjacent layers can move at different velocities without internal resistive stresses. This is expressed mathematically as p_{yx}=2μ˙ε_{yx}=0, indicating that viscosity (μ) is effectively zero. The confusion arises from the interpretation of the rate of angular deformation (˙ε_{yx}), which should not be zero in this context. Additionally, ideal fluids are considered a subset of perfect fluids, aligning with the textbook's definitions. Understanding these distinctions clarifies the relationship between viscosity and shear stress in perfect fluids.
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So the textbook I am reading says that a perfect fluid cannot sustain shear stress, or that p_{yx}=2\mu \dot \epsilon_{yx} =0, where \mu is the viscosity, and \dot \epsilon_{yx} is the rate of angular deformation. Then it says when \dot \epsilon_{yx} =0, this means that "two adjacent horizontal layers of a perfect fluid can move at different velocities without one layer affecting the other layer through internal resistive stresses." This seems to me, however, like what would happen if the viscosity were zero.

Can someone clear up my misconception?
 
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Viscosity is zero in a perfect fluid. The situation described is not ##\dot\epsilon_{xy}=0## but ##\neq 0##.

Edit: Why is \eps not a standard TeX command yet? :headbang:
 
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I think ideal fluids are a subset of perfect fluids, at least according to my book.
 

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