Exponential decay of a pendulum oscillation amplitude

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SUMMARY

The discussion centers on the mathematical manipulation of the exponential decay formula for a pendulum's oscillation amplitude. Specifically, participants clarify the use of the natural logarithm (ln) to simplify the expression involving the amplitude (A) and the exponential term (e^(-t/T)). By applying the properties of logarithms, such as ln(A·B) = ln(A) + ln(B) and ln(A^B) = B·ln(A), the confusion regarding the elimination of the amplitude term is resolved. This approach is essential for solving problems related to oscillatory motion in physics.

PREREQUISITES
  • Understanding of exponential functions and decay
  • Familiarity with natural logarithms (ln) and their properties
  • Basic knowledge of pendulum motion and oscillation
  • Ability to manipulate algebraic expressions
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  • Study the derivation of the exponential decay formula in physics
  • Learn more about the properties of logarithms, particularly in relation to exponential functions
  • Explore the mathematical modeling of oscillatory systems
  • Investigate the applications of logarithmic functions in real-world scenarios
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as anyone looking to strengthen their understanding of logarithmic functions and their applications in mathematical problem-solving.

asilvester635
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Homework Statement


I found an answer on the internet for this problem, but I'm not sure on one of the steps. The solution says, "Take ln of both sides to get rid of Ae. If we do that, then the right side will be ln(Ae^t/T). I don't see how using ln will get rid of Ae?

Homework Equations


Refer to the image in part 3.

The Attempt at a Solution


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Hi, I remember you the property of ##\ln##:

##\ln{(A\cdot B)} \,=\, \ln{A}+\ln{B}##

apply this to the right side ## \ln{(Ae^{-\frac{t}{T}})}##, what is the result ?

Ps. remember also that ##\ln{(A^B)}=B\ln{A}##.
Ssnow
 

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