Exponential function proof problem

rustyjoker
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Homework Statement



Big problem with exponential function proof assignment, need some help.

let
x≥0 and for every k\in N there is n_{k}\in N and

x_{k1}≥...≥x_{k_{nk}} and x_{k1}+...+x_{k_{nk}}=x.
Proof: if lim_{k→}∞ x_{k1}=0 then lim_{k→}∞<br /> <br /> (1+x_{k1})·...·(1+x_{k_{nk}})=exp(x)=e^{x}
 
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rustyjoker said:

Homework Statement



Big problem with exponential function proof assignment, need some help.

let
x≥0 and for every k\in N there is n_{k}\in N and

x_{k1}≥...≥x_{k_{nk}} and x_{k1}+...+x_{k_{nk}}=x.
Proof: if lim_{k→}∞ x_{k1}=0 then lim_{k→}∞<br /> <br /> (1+x_{k1})·...·(1+x_{k_{nk}})=exp(x)=e^{x}

There must be something wrong with the statement of hypotheses, because it allows me to take x_1 = x,\: x_2 = x_3 = \cdots = x_n = 0, giving \lim_{n \rightarrow \infty} (1+x_1) \cdot (1+x_2) \cdots (1+x_n) = 1+x.

RGV
 
Well, for an example if you think about the product
(1+0,009)(1+0,008)⋅...⋅(1+0,001)=1,045879514 and
exp(0,009+...+0,001)=1,046...
I think the idea is to proof that first lim_{k→}∞ n_{k}=∞, then <br /> <br /> lim_{k→}∞ x_{k1}=...=lim_{k→}∞ x_{k_{nk}}=x/n_{k}= 0. So we'd have
lim_{k→∞} (1+x/n_{k})^{n_{k}} = e^{x}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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