How do logarithms and exponential functions relate?

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Exponential functions and logarithms are closely related, as logarithms are the inverse operations of exponentials. Key logarithmic laws include the summation laws, which state that ln(a) + ln(b) equals ln(a*b) and ln(a) + ln(b^{-1}) equals ln(a/b). Understanding these laws can help solve equations involving logarithms more easily. Resources like HyperPhysics and Oak Road Systems provide useful explanations and examples. Mastering these concepts will aid in explaining them effectively to others.
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hi, out daughter doing AS maths is unsure of exponentail functions and how they relate to natural logs. she finds it really hard to solve equations involving logs.

can you help explain the log laws to me so we understand and explain them to her. we hate the embarassed feeling of not knowing what to say.


xxxxx Wayne and Gareth
 
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(Unrelated response) Don't feel too embarassed, there is always a worse case than your own right? My dad couldn't help me with math past algebra I despite having a statistics major :) (thank goodness he is working in a field that doesn't require it or someone would be screwed)

Maybe a more specific question would help, but two laws I didn't see covered in the above link (hyperphysics is a great website by the way) were the summation laws: ln(a) + ln(b) = ln(a*b) or ln(a) + ln(b^{-1}) = ln(a/b)
 
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Here's another link that explains logarithms and the logarithmic rules.

http://oakroadsystems.com/math/loglaws.htm
 
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I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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