Exponentiation Basics: Convert -ve Indices to +ve

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The discussion revolves around converting negative indices to positive ones in the expression (x-m - a-m)/(x - a). A member sought assistance with this problem but later indicated they had solved it. The conversation included clarification on negative indices, specifically that x^{-m} can be expressed as 1/x^m. There was a brief exchange about the importance of engaging with responses in the forum. Overall, the thread highlights the process of understanding and converting negative indices in mathematical expressions.
Raabi
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Hello everyone!

I am a new member of this forum and this is my first post. At the moment, I am looking for the solution for the following:

(x-m - a-m)/(x - a)​

I intend to change the -ve indices into +ve.

Thanks, in anticipation, for any help.

Regards.
 
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Hello!

Ok, so what do negative indices mean? How would you express x^{-m} with a positive index?
 
Thanks for the response, Mentallic. Yes, I meant that; but I have solved the problem. Have a nice time.
 
Please do not post a thread and then refuse to answer any questions about it! Mentallic was trying to find out if you knew that x^{-m}= \frac{1}{x^m}
 
Halls, the guy did nothing wrong. If he claims to have figured out the problem then I'm sure he knows the answer to my question.

Good luck with your studies Raabi!
 
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