Express a as a linear combination of b and c

AI Thread Summary
To express vector a as a linear combination of vectors b and c, the equation a = x*b + y*c is used, where x and y are the coefficients to be determined. The solution can be approached through inspection or by solving simultaneous equations. A matrix can be constructed from the vectors and then reduced to Row Echelon Form (RREF) using Gaussian elimination to find x and y. The provided matrix setup is 1 1 : -1, 2 3 : 3, and 2 5 : 13, which facilitates this process. Ultimately, this method allows for the accurate determination of the coefficients needed to express a in terms of b and c.
Gregg
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Homework Statement



a=\left(<br /> \begin{array}{c}<br /> -1 \\<br /> 3 \\<br /> 13<br /> \end{array}<br /> \right)

b=\left(<br /> \begin{array}{c}<br /> 1 \\<br /> 2 \\<br /> 2<br /> \end{array}<br /> \right)

c=\left(<br /> \begin{array}{c}<br /> 1 \\<br /> 3 \\<br /> 5<br /> \end{array}<br /> \right)


The Attempt at a Solution



Am I supposed to determine this from inspection or through a process?
 
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a=-6b+5c from simultaneous equations its sorted.
 
There is a process you can do to solve this (although some of these problems are easy enough to be solved through inspection). You want to write a as a linear combination of b and c, so write it like this:

x\vec{b} + y\vec{c} = \vec{a}

Then you solve for x and y. This can be done easily by creating a matrix and putting it in RREF.

Your matrix should look like this:

1 1 : -1
2 3 : 3
2 5 : 13

So use Gaussian elimination, put it in RREF and you will have your answers for x and y. (Sorry about the sad looking matrix but I suck with latex lol)
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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