- #1

chiefy

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- Thread starter chiefy
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- #1

chiefy

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- #2

chiefy

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any ideas? anyone?

- #3

GCT

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Suggestion: For each extraction let x equal the weight extracted into the ether layer. In case (a) the concentration in the ether layer is x/100, and in the water layer is (30-x)/300; the ratio of the quantities is equal to k = 20/13.3.

- #4

chiefy

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Well, is this right?

1) k = 20/13.3 = 1.5

x/30-x = .50

x = .5(30-x)

1.5x = 15

x = 10g in ether layer

30 – x = 20g in water layer

x = .5(20 – x)

x = 10 -.5x

1.5x = 10

x = 6.67

20 – x = 13.33

x/13.33 – x =.50

x = .50(13.33 – x)

x = 6.67 - .5x

x = 4.44

13.33 – 4.44 = 8.89

a) 21.1g = three 100-mL portions of ether

x/30-x =1.5

x=1.5(30-x)

x =45-1.5x

2.5x/2.5 =45/2.5

x = 18.0

b) 18.0 g = one 300-mL extraction of ether

- #5

GCT

Science Advisor

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yep everything seems correct

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