F=MA + Average Acceleration etc.

AI Thread Summary
The discussion revolves around a physics homework problem involving a Volkswagen Rabbit's acceleration and force calculations. For part A, the force produced by the engine is calculated using the formula F=ma, resulting in 2640 N based on an average acceleration of 2.42 m/s². In part B, the challenge is to determine how much mass must be removed for the car to achieve the same velocity change in a shorter time with a higher acceleration of 2.90 m/s². The correct approach involves using the force from part A to find the new mass required for the increased acceleration. Ultimately, the solution requires subtracting the new mass from the original mass of 1090 kg.
balllla
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Homework Statement



A. A Volkswagen Rabbit has a mass of 1090 Kg and can go from 0mi/hour to 65 mi/hour in 12.0 seconds with an average acceleartion of 2.42 m/s^2. Disregarding friction, what force must the engine be producing?

B.
Disregarding friction, how much mass would need to be removed from the car above if it were to make the same velocity change in only 10.0 seconds with an average acceleration of 2.90m/s^2.


Homework Equations


f=ma



The Attempt at a Solution



a.f=ma
f=(1090 kg) (2.42m/s^2)
f=2640N

okay I get a but do not understand B. How can the average acceleration be 2.42 m/s^2 when 0mi/hr to 65 mi/hour in 12.0 seconds when it is actually 5.41 m/s^2. Help is needed in finishing the problem then...

thank you.
 
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In part B you are going to use the force you found in part A, NOT the acceleration.
So if you have the same force, but less mass do you think the car can get up to the same speed in more or less time?
 
balllla said:

okay I get a but do not understand B. How can the average acceleration be 2.42 m/s^2 when 0mi/hr to 65 mi/hour in 12.0 seconds when it is actually 5.41 m/s^2. Help is needed in finishing the problem then...


65 mi/hr = 29 m/s

B.
F = 2640 N
a = 2.90 m/s^2
F = ma

Solve for m. This is the mass of the car after some of the original total mass had been removed. Subtract this mass from m = 1090kg
 
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