Fabry Perot Cavity - phase difference?

AI Thread Summary
The discussion revolves around the formula for phase difference in light reflections, specifically δ = (2π/λ)2nlcosθ, where n is the refractive index, l is the distance between cavity walls, and θ is the angle of the ray. The user initially struggles to understand the derivation and purpose of this formula, questioning the need to multiply the wavenumber k by the refractive index and the distance traveled by light. They suggest that the distance traveled should be 2l/cosθ instead. Ultimately, the user resolves their confusion independently. The conversation highlights the complexities of understanding phase differences in optics.
trelek2
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Hi,

I'm having trouble understanding where the formula (appearing in my notes or Wikipedia) comes from.
One can read on Wikipedia: The phase difference between each succeeding reflection is given by
\delta = \frac{2 \pi}{\lambda}2nlcos\theta
Where n is refractive index inside cavity, l distance between cavity walls, \theta angle of the ray.

What are we actually finding?
It would seem we are multiplying wavenumber k by refractive index n and distance traveled by light. But as I look at it, it seems to me that distance traveled is \frac{2l}{cos\theta}. And i don't understand why would we do that to find phase difference. Can anyone explain what are we actually doing here?
 
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nevermind, i found the answer.
 
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