- #1
Liquidice_69
- 12
- 0
im trying to solve this trig equation and the book says to factor it i think but its not clear, could anyone help. thxs
2sin^2 x + 3cos x – 3 = 0
2sin^2 x + 3cos x – 3 = 0
The equation "Factor 2sin^2 x + 3cos x – 3 = 0" is used to solve for the values of x that satisfy the equation. It is commonly used in trigonometry and calculus problems.
To solve the equation "Factor 2sin^2 x + 3cos x – 3 = 0", you can use various algebraic and trigonometric identities and techniques such as factoring, substitution, and the quadratic formula. It is important to also consider the domain of the equation and make sure to check for extraneous solutions.
Yes, the equation "Factor 2sin^2 x + 3cos x – 3 = 0" can have multiple solutions since it is a quadratic equation in terms of sin x. This means that there can be two values of x that satisfy the equation, depending on the values of the coefficients.
The domain of the equation "Factor 2sin^2 x + 3cos x – 3 = 0" is all real numbers since sin x and cos x can take on any value in the real number system. However, when solving the equation, it is important to consider any restrictions or limitations on x that may arise from the problem.
The graph of the equation "Factor 2sin^2 x + 3cos x – 3 = 0" is a sinusoidal curve with a period of 2π and an amplitude of √(2/3). The x-intercepts of the graph represent the solutions to the equation, and the y-intercept is at y = -3. The graph can also be shifted vertically or horizontally depending on the values of the coefficients.