Factor in equation (3.49) of Peskin and Schroeder

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The discussion centers on the 1/2 factor in the exponential of Eq. (3.49) from Peskin and Schroeder's text, specifically regarding the Lorentz boost transformation of a spinor along the z-axis. The user initially misinterprets the factor due to a misunderstanding of the rapidity parameter, η, and its relationship to the angular frequency, ω_{03}. The resolution comes from recognizing the necessity of summing over the indices μ and ν in the expression for the Lorentz transformation, leading to the correct interpretation of the factor as 1/2 rather than 1/4.

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jmlaniel
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My question concerns the 1/2 factor in the exponential of Eq. (3.49) of Peskin and Schroeder.

This equation concerns the Lorentz boost transformation of a spinor along the z-axis (or 3-direction).

According to Eq. (3.26):

S^{03} = -\frac{i}{2}\begin{bmatrix}\sigma^3 & 0 \\0 & -\sigma^3\end{bmatrix}

and Eq. (3.30):

\Lambda_{1/2} = exp(-\frac{i}{2}\omega_{03} S^{03})

Combining these two expressions and using the infinitesimal boost (according to Eq. (3.48) and Eq. (3.21)): \omega_{03} = \eta (here \eta is the rapidity):

\Lambda_{1/2} = exp(-\frac{1}{4}\eta \begin{bmatrix}\sigma^3 & 0 \\0 & -\sigma^3\end{bmatrix})

My problem is that Peskin and Schroeder have a 1/2 factor where my simple substitution gives a 1/4?

Am I misinterpresting the meaning of \omega_{03}? I am assuming that \eta = \beta (v/c) from my understanding of Eq. (3.21)... this might be a problem?!?

Thanks for your help!
 
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jmlaniel said:
[...] and Eq. (3.30):

\Lambda_{1/2} = exp(-\frac{i}{2}\omega_{03} S^{03})
In my version of P&S, eq(3.30) is
$$
\Lambda_{1/2} = exp(-\frac{i}{2}\omega_{\mu\nu} S^{\mu\nu})
$$
and you must sum over ##\mu, \nu##. So you need an exponent involving
$$
(\omega_{03} S^{03} + \omega_{30} S^{30})
$$
Is that enough for you to figure out the rest...?
 
Thanks Strangerep! I just completely forgot the summation over the indices... That was also enough for me to figure out the rest!
 

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