Factoring e^x in a Complex Equation: Tips and Tricks

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e^{2x} - 3e^{x + 1} + 2e^{2} = 0

I've been staring at this for the past while I can't solve it for x...

The only thing I can think of doing is factoring out e^{x}
 
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Try setting u=e^x. Then you'll have a quadratic equation for u.
 
Damn, thanks.
 

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