Factoring Fractions: Solve (x+20)(x+10)^2+400

AI Thread Summary
The discussion focuses on transforming the expression 20(x + 20) / ((x+10)^2 + 400) into a fraction with constants a, b, c, and d. The challenge arises from the presence of the constant 400, which complicates the factorization into real numbers. It is suggested that while complex numbers could potentially be used, the factor of 20 limits the ability to achieve the desired form. The conversation hints at the relevance of this transformation for finding the inverse Laplace transform in circuit analysis. Ultimately, the expression is already in a useful format for inversion, emphasizing the importance of recognizing its current structure.
seang
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how do I make:

20(x + 20) / ((x+10)^2 + 400)

into a fraction like (x-a)(x-b)...etc / (x-c)(x-d)...etc

where a b c d are constants. The 400 is really stumping me.
 
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It's impossible if a, b, c, d, ... have to be real numbers. If they can be complex, then you can do it. Well, actually, no you technically can't do it because of the 20, but you can come closer to your goal.
 
I assume you are asking this to find the inverse Laplace transform for your circuit problems. What you don't see is that the form is already in the form that is useful to be inverted.

Y(s) = 20 \frac {s+20}{(s+10)^2 + 400} = 20 \frac {s + 10 + 10}{(s+10)^2 + 400} = 20 \bigg[ \frac {s+10}{(s+10)^2+400} + \frac {10}{(s+10)^2 + 400}\bigg]

Now look up the Laplace transforms of cosines and sines.
 

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