Failing physics in dire need of help. PLEASE

  • Thread starter Thread starter josher1289
  • Start date Start date
  • Tags Tags
    Failing Physics
AI Thread Summary
To solve the problem of net work done on the wheelbarrow, first calculate the work done by the worker using the formula W = Fd, where F is the applied force and d is the distance. The worker applies a force of 50.0N over a distance of 5.0m, resulting in positive work of 250J. The frictional force of 43N acts in the opposite direction, contributing negative work of -215J over the same distance. The net work is then the sum of the positive and negative work, which equals 35J. Understanding the signs of the forces is crucial for accurately determining the net work.
josher1289
Messages
4
Reaction score
0
A worker pushes a wheelbarrow with a horizontal force of 50.0N over a level distance of 5.0m. If a frictional force of 43N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

how would i go about solving this problem?
 
Physics news on Phys.org
The force applied by the worker is constant and along the direction of displacement and the force done by friction is opposite the direction of displacement so we can use the relation

W = Fd

The net work is the sum of all the works (watch your signs!).
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Failing Physics. Need Dire Help. PLEASE
Replies
2
Views
3K
Calculating Kinetic Energy on an Inclined Ramp with Friction
Replies
21
Views
6K
Calculating Kinetic Energy of a Sliding Wheelbarrow on an Inclined Ramp
Replies
2
Views
2K
Overcoming friction and then some.
Replies
6
Views
3K
Why is using Newton's First Law failing me?
Replies
3
Views
2K
I need opinions on a Projectile Motion problem that I made up
Replies
11
Views
2K
Block drifts off between two moving planes through friction
Replies
21
Views
752
Angular momentum conservation on a merry-go-round
Replies
5
Views
2K
Drone dragging a hose behind it
Replies
24
Views
1K
How to tell when to use Cos vs sin in physics
Replies
10
Views
11K

Hot Threads

Recent Insights

Back
Top