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Fairly basic integral failing to become solved. O:-)

  1. Apr 27, 2009 #1
    "Fairly" basic integral failing to become solved. O:-)

    Hi,

    I'm having trouble with an integral where I simply do not know where to start. I just need a little nudge in the right direction. I've tried integration by parts and by substitution, but I'm really just stumbling in the dark and should obviously choose something in a more well-informed manner. If I could just get a nudge in the right direction I think that I can solve it. :)

    1. The problem statement, all variables and given/known data
    [tex]\int (x^2+z^2)^{-3/2}dx[/tex]
     
  2. jcsd
  3. Apr 27, 2009 #2
    Re: "Fairly" basic integral failing to become solved. O:-)

    when you see a square root in your integrand, you will likely want to attempt trig substitution if there is no other obvious route.

    There are 3 different trig substitutions possible based on the form under the root:

    x = z * sin@
    x = z * tan@
    x = z * sec@

    you should know which one to use based on that form.

    tell us which is the correct substitution, and you should be able to solve it.
     
  4. Apr 27, 2009 #3
    Re: "Fairly" basic integral failing to become solved. O:-)

    I'll have a go at that, thank you very much.
     
  5. Apr 27, 2009 #4

    Mark44

    Staff: Mentor

    Re: "Fairly" basic integral failing to become solved. O:-)

    Try a trig substitution, tan u = x/z. Keep in mind that z^2 is a constant in this integral.
     
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