Fairly easy acceleration problem stumping me

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To calculate the force required to bring a 900 kg object moving at 20 m/s to rest in 0.1 seconds, the acceleration is first determined by dividing the speed by the time interval, resulting in 200 m/s². Using the formula F = M x A, the force is calculated as 180,000 N or 180 kN. An initial miscalculation of 1,800,000 N was corrected after realizing the acceleration was incorrectly based on 200 m/s instead of 20 m/s. The final correct force value is confirmed as 180,000 N or 180 kN. This demonstrates the importance of accurate calculations in physics problems.
alpinecg
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1.Calculate the amount of force required to bring to rest an object of 900 Kg mass that moves with a speed of 20 m/s. The moving object is brought to rest in a time equal
to 0.1 s. Provide your answer in both N and KN units.



i think to solve this i just need to find force F=M x A



3. I divided 20m/s by the time interval of 0.1s to get acceleration then timed it by the mass of 900kg. the answer i got is 1,800,000N or 1800KN
 
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Are not there too many 0-s?

ehild
 
ah yes i times the 0.1 by 200m/s not 20m/s so the answer would be 180,000N or 180KN
 
Correct:smile:

ehild
 
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