Fallin with constant speed what is the force of air resistnace

AI Thread Summary
The discussion centers on calculating the force of air resistance acting on a samara falling at a constant speed of 1.1 m/s. It is established that at constant speed, the force of air resistance equals the gravitational force acting on the samara, which is calculated using the equation F=ma. The initial attempt to calculate the force resulted in an incorrect value of 12.4 N. Participants clarify that the samara experiences both drag and air resistance, and at terminal velocity, these forces balance out. To find the correct air resistance, one should use the gravitational force value and apply it in the context of terminal velocity.
kennymr22
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Homework Statement


A 1.26 samara-the winged fruit of a maple tree-falls toward the ground with a constant speed of 1.1
What is the force of air resistance exerted on the samara?



Homework Equations



F=ma I thought that the force of air resistance would have to be equal to mg

The Attempt at a Solution


I tried 12.4N but said I was wrong, not sure what to do now? Any help please.
 
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Hey man the fruit experience a drag force and a resistive force(air resist) against its motion so the forces in the x direction of the fruit would be f+Fa=ma where f is the drag force and Fa the air resist. constant speed would mean the terminal velocity with that you can find the drag force just use these values and you can find the air resistance.
 
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