A bucket of water of mass 14.9 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.250 m with mass 11.4 kg. The cylinder pivots on a frictionless axle through its center. The bucket is released from rest at the top of a well and falls a distance 10.2 m to the water. You can ignore the weight of the rope.(adsbygoogle = window.adsbygoogle || []).push({});

What is the tension in the rope while the bucket is falling?

With what speed does the bucket strike the water?

What is the time of fall?

While the bucket is falling, what is the force exerted on the cylinder by the axle?

** The gravitational force on the dropping bucket provides all the accelerations: the bucket's downward acceleration and the cylinder's rotational accleration (torque = tangential force x radius of cylinder)

mg - T= ma = F_{bucket}

Torque = I_{cyl}\alpha

alpha = a_{bucket}r

How do I solve this problem now

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# Homework Help: Falling bucket

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